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11130511025233 = 28339330427651
BaseRepresentation
bin1010000111111000011000…
…1001111110010001010001
31110102001210110011200202201
42201332012021332101101
52424330241310301413
635401141451443201
72226103303454215
oct241760611762121
943361713150681
1011130511025233
113601472335946
1212b9201756501
136297ab141082
142a6a10866945
151447e43129dd
hexa1f8627e451

11130511025233 has 4 divisors (see below), whose sum is σ = 11169841453168. Its totient is φ = 11091180597300.

The previous prime is 11130511025173. The next prime is 11130511025243. The reversal of 11130511025233 is 33252011503111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11130511025233 - 217 = 11130510894161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11130511025243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19665213543 + ... + 19665214108.

It is an arithmetic number, because the mean of its divisors is an integer number (2792460363292).

Almost surely, 211130511025233 is an apocalyptic number.

It is an amenable number.

11130511025233 is a deficient number, since it is larger than the sum of its proper divisors (39330427935).

11130511025233 is an equidigital number, since it uses as much as digits as its factorization.

11130511025233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39330427934.

The product of its (nonzero) digits is 2700, while the sum is 28.

Adding to 11130511025233 its reverse (33252011503111), we get a palindrome (44382522528344).

The spelling of 11130511025233 in words is "eleven trillion, one hundred thirty billion, five hundred eleven million, twenty-five thousand, two hundred thirty-three".

Divisors: 1 283 39330427651 11130511025233