Base | Representation |
---|---|
bin | 10100101110111011… |
… | …00011011000101011 |
3 | 1001201202000111010202 |
4 | 22113131203120223 |
5 | 140244021310243 |
6 | 5040304502415 |
7 | 542560201343 |
oct | 122735433053 |
9 | 31652014122 |
10 | 11131041323 |
11 | 47a2201106 |
12 | 21a791aa0b |
13 | 10851190ac |
14 | 778461d23 |
15 | 4523264b8 |
hex | 29776362b |
11131041323 has 4 divisors (see below), whose sum is σ = 11136019440. Its totient is φ = 11126063208.
The previous prime is 11131041287. The next prime is 11131041347. The reversal of 11131041323 is 32314013111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11131041323 - 224 = 11114264107 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11131041295 and 11131041304.
It is not an unprimeable number, because it can be changed into a prime (11131041223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2485703 + ... + 2490176.
It is an arithmetic number, because the mean of its divisors is an integer number (2784004860).
Almost surely, 211131041323 is an apocalyptic number.
11131041323 is a deficient number, since it is larger than the sum of its proper divisors (4978117).
11131041323 is an equidigital number, since it uses as much as digits as its factorization.
11131041323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4978116.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11131041323 its reverse (32314013111), we get a palindrome (43445054434).
The spelling of 11131041323 in words is "eleven billion, one hundred thirty-one million, forty-one thousand, three hundred twenty-three".
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