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11131041403 is a prime number
BaseRepresentation
bin10100101110111011…
…00011011001111011
31001201202000111020201
422113131203121323
5140244021311103
65040304503031
7542560201516
oct122735433173
931652014221
1011131041403
1147a2201179
1221a791aa77
131085119141
14778461d7d
1545232651d
hex29776367b

11131041403 has 2 divisors, whose sum is σ = 11131041404. Its totient is φ = 11131041402.

The previous prime is 11131041367. The next prime is 11131041413. The reversal of 11131041403 is 30414013111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11131041403 - 229 = 10594170491 is a prime.

It is not a weakly prime, because it can be changed into another prime (11131041413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565520701 + 5565520702.

It is an arithmetic number, because the mean of its divisors is an integer number (5565520702).

Almost surely, 211131041403 is an apocalyptic number.

11131041403 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131041403 is an equidigital number, since it uses as much as digits as its factorization.

11131041403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11131041403 its reverse (30414013111), we get a palindrome (41545054514).

The spelling of 11131041403 in words is "eleven billion, one hundred thirty-one million, forty-one thousand, four hundred three".