Base | Representation |
---|---|
bin | 10100101110111011… |
… | …00011011001111011 |
3 | 1001201202000111020201 |
4 | 22113131203121323 |
5 | 140244021311103 |
6 | 5040304503031 |
7 | 542560201516 |
oct | 122735433173 |
9 | 31652014221 |
10 | 11131041403 |
11 | 47a2201179 |
12 | 21a791aa77 |
13 | 1085119141 |
14 | 778461d7d |
15 | 45232651d |
hex | 29776367b |
11131041403 has 2 divisors, whose sum is σ = 11131041404. Its totient is φ = 11131041402.
The previous prime is 11131041367. The next prime is 11131041413. The reversal of 11131041403 is 30414013111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11131041403 - 229 = 10594170491 is a prime.
It is not a weakly prime, because it can be changed into another prime (11131041413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565520701 + 5565520702.
It is an arithmetic number, because the mean of its divisors is an integer number (5565520702).
Almost surely, 211131041403 is an apocalyptic number.
11131041403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131041403 is an equidigital number, since it uses as much as digits as its factorization.
11131041403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11131041403 its reverse (30414013111), we get a palindrome (41545054514).
The spelling of 11131041403 in words is "eleven billion, one hundred thirty-one million, forty-one thousand, four hundred three".
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