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1113111323122 = 2556555661561
BaseRepresentation
bin10000001100101010100…
…110101110000111110010
310221102010122022222210211
4100030222212232013302
5121214122444314442
62211204542414334
7143263636064251
oct20145246560762
93842118288724
101113111323122
1139a082361127
1215b88a8913aa
1380c73256636
143bc36930798
151de4ba92617
hex1032a9ae1f2

1113111323122 has 4 divisors (see below), whose sum is σ = 1669666984686. Its totient is φ = 556555661560.

The previous prime is 1113111323113. The next prime is 1113111323143. The reversal of 1113111323122 is 2213231113111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 659443067721 + 453668255401 = 812061^2 + 673549^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1113111323093 and 1113111323102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278277830779 + ... + 278277830782.

Almost surely, 21113111323122 is an apocalyptic number.

1113111323122 is a deficient number, since it is larger than the sum of its proper divisors (556555661564).

1113111323122 is an equidigital number, since it uses as much as digits as its factorization.

1113111323122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 556555661563.

The product of its digits is 216, while the sum is 22.

Adding to 1113111323122 its reverse (2213231113111), we get a palindrome (3326342436233).

The spelling of 1113111323122 in words is "one trillion, one hundred thirteen billion, one hundred eleven million, three hundred twenty-three thousand, one hundred twenty-two".

Divisors: 1 2 556555661561 1113111323122