11131221141211 has 2 divisors, whose sum is σ = 11131221141212. Its totient is φ = 11131221141210.

The previous prime is 11131221141197. The next prime is 11131221141307. The reversal of 11131221141211 is 11214112213111.

It is a m-pointer prime, because the next prime (11131221141307) can be obtained adding 11131221141211 to its product of digits (96).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11131221141211 is a prime.

It is a super-3 number, since 3×11131221141211³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11131221141511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565610570605 + 5565610570606.

It is an arithmetic number, because the mean of its divisors is an integer number (5565610570606).

Almost surely, 2^{11131221141211} is an apocalyptic number.

11131221141211 is a deficient number, since it is larger than the sum of its proper divisors (1).

11131221141211 is an equidigital number, since it uses as much as digits as its factorization.

11131221141211 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 22.

Adding to 11131221141211 its reverse (11214112213111), we get a palindrome (22345333354322).

The spelling of 11131221141211 in words is "eleven trillion, one hundred thirty-one billion, two hundred twenty-one million, one hundred forty-one thousand, two hundred eleven".