Base | Representation |
---|---|
bin | 11001010011110011100100… |
… | …110110110010101111100011 |
3 | 112121010100021102221201111002 |
4 | 121103303210312302233203 |
5 | 104042214402233341003 |
6 | 1032424042501142215 |
7 | 32306020244551622 |
oct | 3123634466625743 |
9 | 477110242851432 |
10 | 111312212012003 |
11 | 32516275860792 |
12 | 105990766ba96b |
13 | 4a15909431cb2 |
14 | 1d6b77b3356b9 |
15 | cd07457d6a88 |
hex | 653ce4db2be3 |
111312212012003 has 2 divisors, whose sum is σ = 111312212012004. Its totient is φ = 111312212012002.
The previous prime is 111312212011997. The next prime is 111312212012011. The reversal of 111312212012003 is 300210212213111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111312212012003 - 28 = 111312212011747 is a prime.
It is a super-2 number, since 2×1113122120120032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111312202012003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656106006001 + 55656106006002.
It is an arithmetic number, because the mean of its divisors is an integer number (55656106006002).
Almost surely, 2111312212012003 is an apocalyptic number.
111312212012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
111312212012003 is an equidigital number, since it uses as much as digits as its factorization.
111312212012003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 111312212012003 its reverse (300210212213111), we get a palindrome (411522424225114).
The spelling of 111312212012003 in words is "one hundred eleven trillion, three hundred twelve billion, two hundred twelve million, twelve thousand, three".
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