Base | Representation |
---|---|
bin | 10000001100101011010… |
… | …011101001100100100011 |
3 | 10221102011110111100222011 |
4 | 100030223103221210203 |
5 | 121214134003212323 |
6 | 2211210043053351 |
7 | 143264141150056 |
oct | 20145323514443 |
9 | 3842143440864 |
10 | 1113123100963 |
11 | 39a088a75a85 |
12 | 15b892811257 |
13 | 80c7581b483 |
14 | 3bc38318a9d |
15 | 1de4cb1c20d |
hex | 1032b4e9923 |
1113123100963 has 2 divisors, whose sum is σ = 1113123100964. Its totient is φ = 1113123100962.
The previous prime is 1113123100937. The next prime is 1113123101021. The reversal of 1113123100963 is 3690013213111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113123100963 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113127100963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556561550481 + 556561550482.
It is an arithmetic number, because the mean of its divisors is an integer number (556561550482).
Almost surely, 21113123100963 is an apocalyptic number.
1113123100963 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113123100963 is an equidigital number, since it uses as much as digits as its factorization.
1113123100963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 31.
The spelling of 1113123100963 in words is "one trillion, one hundred thirteen billion, one hundred twenty-three million, one hundred thousand, nine hundred sixty-three".
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