Base | Representation |
---|---|
bin | 1010000111111011101111… |
… | …1011010001111100111001 |
3 | 1110102011010022200001011221 |
4 | 2201332323323101330321 |
5 | 2424334113231041403 |
6 | 35401411155152041 |
7 | 2226134536364206 |
oct | 241767373217471 |
9 | 43364108601157 |
10 | 11131413143353 |
11 | 3601895584608 |
12 | 12b94138a5621 |
13 | 6298c2cc9889 |
14 | 2a6a985b4cad |
15 | 14484860bdbd |
hex | a1fbbed1f39 |
11131413143353 has 2 divisors, whose sum is σ = 11131413143354. Its totient is φ = 11131413143352.
The previous prime is 11131413143317. The next prime is 11131413143371. The reversal of 11131413143353 is 35334131413111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7253046149904 + 3878366993449 = 2693148^2 + 1969357^2 .
It is a cyclic number.
It is not a de Polignac number, because 11131413143353 - 217 = 11131413012281 is a prime.
It is a super-2 number, since 2×111314131433532 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11131413143453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565706571676 + 5565706571677.
It is an arithmetic number, because the mean of its divisors is an integer number (5565706571677).
Almost surely, 211131413143353 is an apocalyptic number.
It is an amenable number.
11131413143353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131413143353 is an equidigital number, since it uses as much as digits as its factorization.
11131413143353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19440, while the sum is 34.
Adding to 11131413143353 its reverse (35334131413111), we get a palindrome (46465544556464).
The spelling of 11131413143353 in words is "eleven trillion, one hundred thirty-one billion, four hundred thirteen million, one hundred forty-three thousand, three hundred fifty-three".
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