Search a number
-
+
111320102213002 = 255660051106501
BaseRepresentation
bin11001010011111010111011…
…001001100001010110001010
3112121011002122022202110110201
4121103322323021201112022
5104042332032131304002
61032431425435402414
732306416623265234
oct3123727311412612
9477132568673421
10111320102213002
1132519654654561
121059a6b8bb340a
134a16595cb0397
141d6bcc91bb254
15cd0a58344087
hex653ebb26158a

111320102213002 has 4 divisors (see below), whose sum is σ = 166980153319506. Its totient is φ = 55660051106500.

The previous prime is 111320102212939. The next prime is 111320102213003. The reversal of 111320102213002 is 200312201023111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 70483899729961 + 40836202483041 = 8395469^2 + 6390321^2 .

It is not an unprimeable number, because it can be changed into a prime (111320102213003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27830025553249 + ... + 27830025553252.

Almost surely, 2111320102213002 is an apocalyptic number.

111320102213002 is a deficient number, since it is larger than the sum of its proper divisors (55660051106504).

111320102213002 is an equidigital number, since it uses as much as digits as its factorization.

111320102213002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55660051106503.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 111320102213002 its reverse (200312201023111), we get a palindrome (311632303236113).

The spelling of 111320102213002 in words is "one hundred eleven trillion, three hundred twenty billion, one hundred two million, two hundred thirteen thousand, two".

Divisors: 1 2 55660051106501 111320102213002