Base | Representation |
---|---|
bin | 11001010011111010111011… |
… | …001001100001010110001010 |
3 | 112121011002122022202110110201 |
4 | 121103322323021201112022 |
5 | 104042332032131304002 |
6 | 1032431425435402414 |
7 | 32306416623265234 |
oct | 3123727311412612 |
9 | 477132568673421 |
10 | 111320102213002 |
11 | 32519654654561 |
12 | 1059a6b8bb340a |
13 | 4a16595cb0397 |
14 | 1d6bcc91bb254 |
15 | cd0a58344087 |
hex | 653ebb26158a |
111320102213002 has 4 divisors (see below), whose sum is σ = 166980153319506. Its totient is φ = 55660051106500.
The previous prime is 111320102212939. The next prime is 111320102213003. The reversal of 111320102213002 is 200312201023111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 70483899729961 + 40836202483041 = 8395469^2 + 6390321^2 .
It is not an unprimeable number, because it can be changed into a prime (111320102213003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27830025553249 + ... + 27830025553252.
Almost surely, 2111320102213002 is an apocalyptic number.
111320102213002 is a deficient number, since it is larger than the sum of its proper divisors (55660051106504).
111320102213002 is an equidigital number, since it uses as much as digits as its factorization.
111320102213002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55660051106503.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 111320102213002 its reverse (200312201023111), we get a palindrome (311632303236113).
The spelling of 111320102213002 in words is "one hundred eleven trillion, three hundred twenty billion, one hundred two million, two hundred thirteen thousand, two".
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