Base | Representation |
---|---|
bin | 1010000111111110010011… |
… | …1111110111001100010011 |
3 | 1110102012220100021021100211 |
4 | 2201333210333313030103 |
5 | 2424342021131212243 |
6 | 35402003412224551 |
7 | 2226160604351623 |
oct | 241774477671423 |
9 | 43365810237324 |
10 | 11132102210323 |
11 | 3602109536846 |
12 | 12b958660b157 |
13 | 6299a29ab803 |
14 | 2a6b21d04883 |
15 | 144888d6ed9d |
hex | a1fe4ff7313 |
11132102210323 has 2 divisors, whose sum is σ = 11132102210324. Its totient is φ = 11132102210322.
The previous prime is 11132102210309. The next prime is 11132102210387. The reversal of 11132102210323 is 32301220123111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11132102210323 - 217 = 11132102079251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11132102210294 and 11132102210303.
It is not a weakly prime, because it can be changed into another prime (11132102217323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566051105161 + 5566051105162.
It is an arithmetic number, because the mean of its divisors is an integer number (5566051105162).
Almost surely, 211132102210323 is an apocalyptic number.
11132102210323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132102210323 is an equidigital number, since it uses as much as digits as its factorization.
11132102210323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11132102210323 its reverse (32301220123111), we get a palindrome (43433322333434).
The spelling of 11132102210323 in words is "eleven trillion, one hundred thirty-two billion, one hundred two million, two hundred ten thousand, three hundred twenty-three".
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