Base | Representation |
---|---|
bin | 10000001100110001011… |
… | …001001101101111101011 |
3 | 10221102102120122201021021 |
4 | 100030301121031233223 |
5 | 121214341124120042 |
6 | 2211224131553311 |
7 | 143266521161302 |
oct | 20146131155753 |
9 | 3842376581237 |
10 | 1113225223147 |
11 | 39a130686984 |
12 | 15b900a5b837 |
13 | 80c90a25bbb |
14 | 3bc47add439 |
15 | 1de56a90867 |
hex | 1033164dbeb |
1113225223147 has 2 divisors, whose sum is σ = 1113225223148. Its totient is φ = 1113225223146.
The previous prime is 1113225223127. The next prime is 1113225223189. The reversal of 1113225223147 is 7413225223111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113225223147 - 239 = 563469409259 is a prime.
It is not a weakly prime, because it can be changed into another prime (1113225223127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556612611573 + 556612611574.
It is an arithmetic number, because the mean of its divisors is an integer number (556612611574).
Almost surely, 21113225223147 is an apocalyptic number.
1113225223147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113225223147 is an equidigital number, since it uses as much as digits as its factorization.
1113225223147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20160, while the sum is 34.
The spelling of 1113225223147 in words is "one trillion, one hundred thirteen billion, two hundred twenty-five million, two hundred twenty-three thousand, one hundred forty-seven".
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