Base | Representation |
---|---|
bin | 1010000111111111100000… |
… | …1100101100001101001111 |
3 | 1110102020201210102011121211 |
4 | 2201333320030230031033 |
5 | 2424343201112342203 |
6 | 35402055400435251 |
7 | 2226201565411240 |
oct | 241777014541517 |
9 | 43366653364554 |
10 | 11132424340303 |
11 | 3602264355872 |
12 | 12b9656478b27 |
13 | 629a24657376 |
14 | 2a6b529d8cc7 |
15 | 1448a72a0c6d |
hex | a1ff832c34f |
11132424340303 has 32 divisors (see below), whose sum is σ = 12781075507200. Its totient is φ = 9498477913344.
The previous prime is 11132424340291. The next prime is 11132424340313. The reversal of 11132424340303 is 30304342423111.
It is a de Polignac number, because none of the positive numbers 2k-11132424340303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11132424340313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4821317313 + ... + 4821319621.
It is an arithmetic number, because the mean of its divisors is an integer number (399408609600).
Almost surely, 211132424340303 is an apocalyptic number.
11132424340303 is a deficient number, since it is larger than the sum of its proper divisors (1648651166897).
11132424340303 is a wasteful number, since it uses less digits than its factorization.
11132424340303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5719.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 11132424340303 its reverse (30304342423111), we get a palindrome (41436766763414).
It can be divided in two parts, 1113242 and 4340303, that added together give a palindrome (5453545).
The spelling of 11132424340303 in words is "eleven trillion, one hundred thirty-two billion, four hundred twenty-four million, three hundred forty thousand, three hundred three".
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