Base | Representation |
---|---|
bin | 1010000111111111100100… |
… | …0010001000010011101011 |
3 | 1110102020202202202212222202 |
4 | 2201333321002020103223 |
5 | 2424343213204132120 |
6 | 35402101021010415 |
7 | 2226202125445103 |
oct | 241777102102353 |
9 | 43366682685882 |
10 | 11132438349035 |
11 | 3602271253833 |
12 | 12b965b0b3a0b |
13 | 629a27520763 |
14 | 2a6b54804203 |
15 | 1448a861b875 |
hex | a1ff90884eb |
11132438349035 has 16 divisors (see below), whose sum is σ = 14083260383232. Its totient is φ = 8435286156000.
The previous prime is 11132438349031. The next prime is 11132438349037. The reversal of 11132438349035 is 53094383423111.
11132438349035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11132438349035 - 22 = 11132438349031 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (47).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11132438349031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 764058491 + ... + 764073060.
It is an arithmetic number, because the mean of its divisors is an integer number (880203773952).
Almost surely, 211132438349035 is an apocalyptic number.
11132438349035 is a deficient number, since it is larger than the sum of its proper divisors (2950822034197).
11132438349035 is a wasteful number, since it uses less digits than its factorization.
11132438349035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1528131634.
The product of its (nonzero) digits is 933120, while the sum is 47.
The spelling of 11132438349035 in words is "eleven trillion, one hundred thirty-two billion, four hundred thirty-eight million, three hundred forty-nine thousand, thirty-five".
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