Base | Representation |
---|---|
bin | 11001010011111110111101… |
… | …010110000100001011000001 |
3 | 112121011111211012211012210221 |
4 | 121103332331112010023001 |
5 | 104042414420102214410 |
6 | 1032433423341223041 |
7 | 32306632153126222 |
oct | 3123767526041301 |
9 | 477144735735727 |
10 | 111324434023105 |
11 | 32520477869606 |
12 | 1059b507861a81 |
13 | 4a16b06589724 |
14 | 1d6c1ba625249 |
15 | cd0c0d7ad4da |
hex | 653fbd5842c1 |
111324434023105 has 16 divisors (see below), whose sum is σ = 136432046870784. Its totient is φ = 87164407636480.
The previous prime is 111324434023097. The next prime is 111324434023123. The reversal of 111324434023105 is 501320434423111.
It is not a de Polignac number, because 111324434023105 - 23 = 111324434023097 is a prime.
It is a super-2 number, since 2×1113244340231052 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 140914650 + ... + 141702460.
It is an arithmetic number, because the mean of its divisors is an integer number (8527002929424).
Almost surely, 2111324434023105 is an apocalyptic number.
It is an amenable number.
111324434023105 is a deficient number, since it is larger than the sum of its proper divisors (25107612847679).
111324434023105 is an equidigital number, since it uses as much as digits as its factorization.
111324434023105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1389176.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 111324434023105 its reverse (501320434423111), we get a palindrome (612644868446216).
The spelling of 111324434023105 in words is "one hundred eleven trillion, three hundred twenty-four billion, four hundred thirty-four million, twenty-three thousand, one hundred five".
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