1113310231113 has 4 divisors (see below), whose sum is σ = 1484413641488. Its totient is φ = 742206820740.

The previous prime is 1113310231093. The next prime is 1113310231123. The reversal of 1113310231113 is 3111320133111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1113310231113 - 2²¹ = 1113308133961 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1113310231113.

It is not an unprimeable number, because it can be changed into a prime (1113310231123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185551705183 + ... + 185551705188.

It is an arithmetic number, because the mean of its divisors is an integer number (371103410372).

Almost surely, 2^{1113310231113} is an apocalyptic number.

It is an amenable number.

1113310231113 is a deficient number, since it is larger than the sum of its proper divisors (371103410375).

1113310231113 is an equidigital number, since it uses as much as digits as its factorization.

1113310231113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 371103410374.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1113310231113 its reverse (3111320133111), we get a palindrome (4224630364224).

The spelling of 1113310231113 in words is "one trillion, one hundred thirteen billion, three hundred ten million, two hundred thirty-one thousand, one hundred thirteen".