1113310301321 has 4 divisors (see below), whose sum is σ = 1113335990544. Its totient is φ = 1113284612100.

The previous prime is 1113310301291. The next prime is 1113310301347. The reversal of 1113310301321 is 1231030133111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113310301321 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113310301293 and 1113310301302.

It is not an unprimeable number, because it can be changed into a prime (1113310301381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12779495 + ... + 12866316.

It is an arithmetic number, because the mean of its divisors is an integer number (278333997636).

Almost surely, 2^{1113310301321} is an apocalyptic number.

It is an amenable number.

1113310301321 is a deficient number, since it is larger than the sum of its proper divisors (25689223).

1113310301321 is an equidigital number, since it uses as much as digits as its factorization.

1113310301321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25689222.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1113310301321 its reverse (1231030133111), we get a palindrome (2344340434432).

The spelling of 1113310301321 in words is "one trillion, one hundred thirteen billion, three hundred ten million, three hundred one thousand, three hundred twenty-one".