1113311012113 has 4 divisors (see below), whose sum is σ = 1171906328560. Its totient is φ = 1054715695668.

The previous prime is 1113311012087. The next prime is 1113311012119. The reversal of 1113311012113 is 3112101133111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113311012113 - 2²¹ = 1113308914961 is a prime.

It is a super-2 number, since 2×1113311012113² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 58595316427 = 1113311012113 / (1 + 1 + 1 + 3 + 3 + 1 + 1 + 0 + 1 + 2 + 1 + 1 + 3).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1113311012119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29297658195 + ... + 29297658232.

It is an arithmetic number, because the mean of its divisors is an integer number (292976582140).

Almost surely, 2^{1113311012113} is an apocalyptic number.

It is an amenable number.

1113311012113 is a deficient number, since it is larger than the sum of its proper divisors (58595316447).

1113311012113 is an equidigital number, since it uses as much as digits as its factorization.

1113311012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58595316446.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1113311012113 its reverse (3112101133111), we get a palindrome (4225412145224).

The spelling of 1113311012113 in words is "one trillion, one hundred thirteen billion, three hundred eleven million, twelve thousand, one hundred thirteen".