11133132030001 has 4 divisors (see below), whose sum is σ = 11133175590000. Its totient is φ = 11133088470004.

The previous prime is 11133132029917. The next prime is 11133132030023. The reversal of 11133132030001 is 10003023133111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11133132030001 - 2³³ = 11124542095409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11133132031001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21394351 + ... + 21908548.

It is an arithmetic number, because the mean of its divisors is an integer number (2783293897500).

Almost surely, 2^{11133132030001} is an apocalyptic number.

It is an amenable number.

11133132030001 is a deficient number, since it is larger than the sum of its proper divisors (43559999).

11133132030001 is an equidigital number, since it uses as much as digits as its factorization.

11133132030001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43559998.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11133132030001 its reverse (10003023133111), we get a palindrome (21136155163112).

The spelling of 11133132030001 in words is "eleven trillion, one hundred thirty-three billion, one hundred thirty-two million, thirty thousand, one".