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1113313211233 is a prime number
BaseRepresentation
bin10000001100110110101…
…000110111001101100001
310221102122201012222020021
4100030312220313031201
5121220031140224413
62211240553513441
7143301640104316
oct20146650671541
93842581188207
101113313211233
1139a176313703
1215b926412881
1380ca6022162
143bc55684d0d
151de5e67118d
hex10336a37361

1113313211233 has 2 divisors, whose sum is σ = 1113313211234. Its totient is φ = 1113313211232.

The previous prime is 1113313211177. The next prime is 1113313211237. The reversal of 1113313211233 is 3321123133111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 931489428769 + 181823782464 = 965137^2 + 426408^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1113313211233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1113313211198 and 1113313211207.

It is not a weakly prime, because it can be changed into another prime (1113313211237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556656605616 + 556656605617.

It is an arithmetic number, because the mean of its divisors is an integer number (556656605617).

Almost surely, 21113313211233 is an apocalyptic number.

It is an amenable number.

1113313211233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113313211233 is an equidigital number, since it uses as much as digits as its factorization.

1113313211233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 25.

Adding to 1113313211233 its reverse (3321123133111), we get a palindrome (4434436344344).

The spelling of 1113313211233 in words is "one trillion, one hundred thirteen billion, three hundred thirteen million, two hundred eleven thousand, two hundred thirty-three".