Base | Representation |
---|---|
bin | 10000001100110111101… |
… | …000111001111101000001 |
3 | 10221102200212210220122122 |
4 | 100030313220321331001 |
5 | 121220044434442211 |
6 | 2211242353414025 |
7 | 143302232566244 |
oct | 20146750717501 |
9 | 3842625726578 |
10 | 1113329999681 |
11 | 39a184840059 |
12 | 15b92bb6a315 |
13 | 80ca964c853 |
14 | 3bc579b525b |
15 | 1de60d8a6db |
hex | 10337a39f41 |
1113329999681 has 2 divisors, whose sum is σ = 1113329999682. Its totient is φ = 1113329999680.
The previous prime is 1113329999629. The next prime is 1113329999699. The reversal of 1113329999681 is 1869999233111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1078357633600 + 34972366081 = 1038440^2 + 187009^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113329999681 - 230 = 1112256257857 is a prime.
It is a super-2 number, since 2×11133299996812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1113329999981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556664999840 + 556664999841.
It is an arithmetic number, because the mean of its divisors is an integer number (556664999841).
Almost surely, 21113329999681 is an apocalyptic number.
It is an amenable number.
1113329999681 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113329999681 is an equidigital number, since it uses as much as digits as its factorization.
1113329999681 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5668704, while the sum is 62.
The spelling of 1113329999681 in words is "one trillion, one hundred thirteen billion, three hundred twenty-nine million, nine hundred ninety-nine thousand, six hundred eighty-one".
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