111333000121 has 4 divisors (see below), whose sum is σ = 127237714432. Its totient is φ = 95428285812.

The previous prime is 111333000109. The next prime is 111333000137. The reversal of 111333000121 is 121000333111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111333000121 - 2¹⁵ = 111332967353 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111333000095 and 111333000104.

It is not an unprimeable number, because it can be changed into a prime (111333000151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7952357145 + ... + 7952357158.

It is an arithmetic number, because the mean of its divisors is an integer number (31809428608).

Almost surely, 2^111333000121 is an apocalyptic number.

It is an amenable number.

111333000121 is a deficient number, since it is larger than the sum of its proper divisors (15904714311).

111333000121 is an equidigital number, since it uses as much as digits as its factorization.

111333000121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15904714310.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 111333000121 its reverse (121000333111), we get a palindrome (232333333232).

The spelling of 111333000121 in words is "one hundred eleven billion, three hundred thirty-three million, one hundred twenty-one", and thus it is an aban number.