Base | Representation |
---|---|
bin | 10000001100111100000… |
… | …000100100101110010001 |
3 | 10221102212222202121200021 |
4 | 100030330000210232101 |
5 | 121220222222004131 |
6 | 2211253533023441 |
7 | 143304113002645 |
oct | 20147400445621 |
9 | 3842788677607 |
10 | 1113403313041 |
11 | 39a212164508 |
12 | 15b950624b81 |
13 | 80cbb8ab536 |
14 | 3bc6361ac25 |
15 | 1de6751ce11 |
hex | 1033c024b91 |
1113403313041 has 2 divisors, whose sum is σ = 1113403313042. Its totient is φ = 1113403313040.
The previous prime is 1113403312963. The next prime is 1113403313051. The reversal of 1113403313041 is 1403133043111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 936822666816 + 176580646225 = 967896^2 + 420215^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113403313041 - 29 = 1113403312529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1113403312997 and 1113403313015.
It is not a weakly prime, because it can be changed into another prime (1113403313051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556701656520 + 556701656521.
It is an arithmetic number, because the mean of its divisors is an integer number (556701656521).
Almost surely, 21113403313041 is an apocalyptic number.
It is an amenable number.
1113403313041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113403313041 is an equidigital number, since it uses as much as digits as its factorization.
1113403313041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1113403313041 its reverse (1403133043111), we get a palindrome (2516536356152).
The spelling of 1113403313041 in words is "one trillion, one hundred thirteen billion, four hundred three million, three hundred thirteen thousand, forty-one".
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