Base | Representation |
---|---|
bin | 10000001100111100011… |
… | …111001101011111000011 |
3 | 10221102220112212122112011 |
4 | 100030330133031133003 |
5 | 121220231301004243 |
6 | 2211254421113351 |
7 | 143304241162525 |
oct | 20147437153703 |
9 | 3842815778464 |
10 | 1113411344323 |
11 | 39a21674a533 |
12 | 15b953258857 |
13 | 80cc0460c85 |
14 | 3bc6470ba15 |
15 | 1de680a789d |
hex | 1033c7cd7c3 |
1113411344323 has 2 divisors, whose sum is σ = 1113411344324. Its totient is φ = 1113411344322.
The previous prime is 1113411344261. The next prime is 1113411344333. The reversal of 1113411344323 is 3234431143111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1113411344323 - 217 = 1113411213251 is a prime.
It is a super-5 number, since 5×11134113443235 (a number of 61 digits) contains 55555 as substring.
It is not a weakly prime, because it can be changed into another prime (1113411344333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556705672161 + 556705672162.
It is an arithmetic number, because the mean of its divisors is an integer number (556705672162).
Almost surely, 21113411344323 is an apocalyptic number.
1113411344323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113411344323 is an equidigital number, since it uses as much as digits as its factorization.
1113411344323 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 31.
Adding to 1113411344323 its reverse (3234431143111), we get a palindrome (4347842487434).
The spelling of 1113411344323 in words is "one trillion, one hundred thirteen billion, four hundred eleven million, three hundred forty-four thousand, three hundred twenty-three".
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