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111343113403 = 1031696363727
BaseRepresentation
bin110011110110010010…
…0010001010010111011
3101122101200201012120221
41213230210101102323
53311012314112103
6123052245200511
711021120563654
oct1475444212273
9348350635527
10111343113403
1143247315095
12196b4700137
13a66584b872
14556372852b
152d69ea21bd
hex19ec9114bb

111343113403 has 8 divisors (see below), whose sum is σ = 112432506368. Its totient is φ = 110253882024.

The previous prime is 111343113389. The next prime is 111343113407. The reversal of 111343113403 is 304311343111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 111343113403 - 221 = 111341016251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111343113407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1715326 + ... + 1779052.

It is an arithmetic number, because the mean of its divisors is an integer number (14054063296).

Almost surely, 2111343113403 is an apocalyptic number.

111343113403 is a deficient number, since it is larger than the sum of its proper divisors (1089392965).

111343113403 is a wasteful number, since it uses less digits than its factorization.

111343113403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80793.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 111343113403 its reverse (304311343111), we get a palindrome (415654456514).

The spelling of 111343113403 in words is "one hundred eleven billion, three hundred forty-three million, one hundred thirteen thousand, four hundred three".

Divisors: 1 103 16963 63727 1747189 6563881 1081001101 111343113403