11134320401331 has 12 divisors (see below), whose sum is σ = 16089577915320. Its totient is φ = 7419801497280.

The previous prime is 11134320401279. The next prime is 11134320401333. The reversal of 11134320401331 is 13310402343111.

11134320401331 is a `hidden beast` number, since 1 + 1 + 1 + 3 + 4 + 320 + 4 + 0 + 1 + 331 = 666.

It is not a de Polignac number, because 11134320401331 - 2¹³ = 11134320393139 is a prime.

It is a super-2 number, since 2×11134320401331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11134320401295 and 11134320401304.

It is not an unprimeable number, because it can be changed into a prime (11134320401333) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 256541286 + ... + 256584683.

It is an arithmetic number, because the mean of its divisors is an integer number (1340798159610).

Almost surely, 2^{11134320401331} is an apocalyptic number.

11134320401331 is a deficient number, since it is larger than the sum of its proper divisors (4955257513989).

11134320401331 is a wasteful number, since it uses less digits than its factorization.

11134320401331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 513128386 (or 513128383 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 11134320401331 its reverse (13310402343111), we get a palindrome (24444722744442).

The spelling of 11134320401331 in words is "eleven trillion, one hundred thirty-four billion, three hundred twenty million, four hundred one thousand, three hundred thirty-one".