Base | Representation |
---|---|
bin | 1010001000000110111100… |
… | …1010000001100101000001 |
3 | 1110102102212212211210112221 |
4 | 2202001233022001211001 |
5 | 2424411243023130423 |
6 | 35403025413251041 |
7 | 2226302211346360 |
oct | 242015712014501 |
9 | 43372785753487 |
10 | 11134420130113 |
11 | 3603098987235 |
12 | 12b9b12933a81 |
13 | 629c81c89297 |
14 | 2a6ca1ab97d7 |
15 | 1449725d0e5d |
hex | a206f281941 |
11134420130113 has 4 divisors (see below), whose sum is σ = 12725051577280. Its totient is φ = 9543788682948.
The previous prime is 11134420130089. The next prime is 11134420130131. The reversal of 11134420130113 is 31103102443111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11134420130113 - 237 = 10996981176641 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11134420130213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 795315723573 + ... + 795315723586.
It is an arithmetic number, because the mean of its divisors is an integer number (3181262894320).
Almost surely, 211134420130113 is an apocalyptic number.
It is an amenable number.
11134420130113 is a deficient number, since it is larger than the sum of its proper divisors (1590631447167).
11134420130113 is an equidigital number, since it uses as much as digits as its factorization.
11134420130113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1590631447166.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 11134420130113 its reverse (31103102443111), we get a palindrome (42237522573224).
The spelling of 11134420130113 in words is "eleven trillion, one hundred thirty-four billion, four hundred twenty million, one hundred thirty thousand, one hundred thirteen".
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