11135251314113 has 4 divisors (see below), whose sum is σ = 11136301721028. Its totient is φ = 11134200907200.

The previous prime is 11135251314101. The next prime is 11135251314151. The reversal of 11135251314113 is 31141315253111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7158369813169 + 3976881500944 = 2675513^2 + 1994212^2 .

It is a cyclic number.

It is not a de Polignac number, because 11135251314113 - 2¹⁰ = 11135251313089 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11135251314113.

It is not an unprimeable number, because it can be changed into a prime (11135251319113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 525187556 + ... + 525208757.

It is an arithmetic number, because the mean of its divisors is an integer number (2784075430257).

Almost surely, 2^{11135251314113} is an apocalyptic number.

It is an amenable number.

11135251314113 is a deficient number, since it is larger than the sum of its proper divisors (1050406915).

11135251314113 is a wasteful number, since it uses less digits than its factorization.

11135251314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1050406914.

The product of its digits is 5400, while the sum is 32.

Adding to 11135251314113 its reverse (31141315253111), we get a palindrome (42276566567224).

The spelling of 11135251314113 in words is "eleven trillion, one hundred thirty-five billion, two hundred fifty-one million, three hundred fourteen thousand, one hundred thirteen".