Base | Representation |
---|---|
bin | 110011110110101001… |
… | …0011011010101100001 |
3 | 101122102112110221022211 |
4 | 1213231102123111201 |
5 | 3311023413310103 |
6 | 123053400402121 |
7 | 11021325460132 |
oct | 1475522332541 |
9 | 348375427284 |
10 | 111355213153 |
11 | 43253129888 |
12 | 196b8776341 |
13 | a6681c7092 |
14 | 5565197c89 |
15 | 2d6b09236d |
hex | 19ed49b561 |
111355213153 has 2 divisors, whose sum is σ = 111355213154. Its totient is φ = 111355213152.
The previous prime is 111355213147. The next prime is 111355213183. The reversal of 111355213153 is 351312553111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91556471889 + 19798741264 = 302583^2 + 140708^2 .
It is a cyclic number.
It is not a de Polignac number, because 111355213153 - 29 = 111355212641 is a prime.
It is not a weakly prime, because it can be changed into another prime (111355213183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55677606576 + 55677606577.
It is an arithmetic number, because the mean of its divisors is an integer number (55677606577).
Almost surely, 2111355213153 is an apocalyptic number.
It is an amenable number.
111355213153 is a deficient number, since it is larger than the sum of its proper divisors (1).
111355213153 is an equidigital number, since it uses as much as digits as its factorization.
111355213153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6750, while the sum is 31.
Adding to 111355213153 its reverse (351312553111), we get a palindrome (462667766264).
The spelling of 111355213153 in words is "one hundred eleven billion, three hundred fifty-five million, two hundred thirteen thousand, one hundred fifty-three".
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