Base | Representation |
---|---|
bin | 10100101111011111… |
… | …11010011111001001 |
3 | 1001202002002000121221 |
4 | 22113233322133021 |
5 | 140301234321122 |
6 | 5041000002041 |
7 | 542646126133 |
oct | 122757723711 |
9 | 31662060557 |
10 | 11135854537 |
11 | 47a4999375 |
12 | 21a9460321 |
13 | 1086112b52 |
14 | 778d56053 |
15 | 4529776c7 |
hex | 297bfa7c9 |
11135854537 has 2 divisors, whose sum is σ = 11135854538. Its totient is φ = 11135854536.
The previous prime is 11135854519. The next prime is 11135854553. The reversal of 11135854537 is 73545853111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9631655881 + 1504198656 = 98141^2 + 38784^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11135854537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11135854493 and 11135854502.
It is not a weakly prime, because it can be changed into another prime (11135854567) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567927268 + 5567927269.
It is an arithmetic number, because the mean of its divisors is an integer number (5567927269).
Almost surely, 211135854537 is an apocalyptic number.
It is an amenable number.
11135854537 is a deficient number, since it is larger than the sum of its proper divisors (1).
11135854537 is an equidigital number, since it uses as much as digits as its factorization.
11135854537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 252000, while the sum is 43.
The spelling of 11135854537 in words is "eleven billion, one hundred thirty-five million, eight hundred fifty-four thousand, five hundred thirty-seven".
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