Base | Representation |
---|---|
bin | 110011110110110100… |
… | …1010100100000010011 |
3 | 101122102221202211121022 |
4 | 1213231221110200103 |
5 | 3311031432330413 |
6 | 123054133150055 |
7 | 11021430463541 |
oct | 1475551244023 |
9 | 348387684538 |
10 | 111361214483 |
11 | 43256558762 |
12 | 196ba78b32b |
13 | a66951886c |
14 | 5565cbad91 |
15 | 2d6b87a608 |
hex | 19eda54813 |
111361214483 has 2 divisors, whose sum is σ = 111361214484. Its totient is φ = 111361214482.
The previous prime is 111361214479. The next prime is 111361214513. The reversal of 111361214483 is 384412163111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111361214483 - 22 = 111361214479 is a prime.
It is a super-2 number, since 2×1113612144832 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (111361214383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55680607241 + 55680607242.
It is an arithmetic number, because the mean of its divisors is an integer number (55680607242).
Almost surely, 2111361214483 is an apocalyptic number.
111361214483 is a deficient number, since it is larger than the sum of its proper divisors (1).
111361214483 is an equidigital number, since it uses as much as digits as its factorization.
111361214483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13824, while the sum is 35.
Adding to 111361214483 its reverse (384412163111), we get a palindrome (495773377594).
The spelling of 111361214483 in words is "one hundred eleven billion, three hundred sixty-one million, two hundred fourteen thousand, four hundred eighty-three".
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