Base | Representation |
---|---|
bin | 1010001000011100000111… |
… | …0000111111011110011010 |
3 | 1110102222112210111010112111 |
4 | 2202013001300333132122 |
5 | 2430004411331402442 |
6 | 35405405231102534 |
7 | 2226563042334031 |
oct | 242070160773632 |
9 | 43388483433474 |
10 | 11140101044122 |
11 | 3605543687a96 |
12 | 12bb039371a4a |
13 | 62a678c03b6b |
14 | 2a7280387718 |
15 | 144ba61d9b17 |
hex | a21c1c3f79a |
11140101044122 has 4 divisors (see below), whose sum is σ = 16710151566186. Its totient is φ = 5570050522060.
The previous prime is 11140101044113. The next prime is 11140101044129. The reversal of 11140101044122 is 22144010104111.
11140101044122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11057812958241 + 82288085881 = 3325329^2 + 286859^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11140101044093 and 11140101044102.
It is not an unprimeable number, because it can be changed into a prime (11140101044129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2785025261029 + ... + 2785025261032.
Almost surely, 211140101044122 is an apocalyptic number.
11140101044122 is a deficient number, since it is larger than the sum of its proper divisors (5570050522064).
11140101044122 is an equidigital number, since it uses as much as digits as its factorization.
11140101044122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5570050522063.
The product of its (nonzero) digits is 256, while the sum is 22.
Adding to 11140101044122 its reverse (22144010104111), we get a palindrome (33284111148233).
The spelling of 11140101044122 in words is "eleven trillion, one hundred forty billion, one hundred one million, forty-four thousand, one hundred twenty-two".
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