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11140414121 is a prime number
BaseRepresentation
bin10100110000000010…
…10011101010101001
31001202101122200012102
422120001103222221
5140303421222441
65041241423145
7543032646314
oct123001235251
931671580172
1011140414121
1147a7523021
1221aaa9aab5
13108704b325
147797c197b
1545307869b
hex298053aa9

11140414121 has 2 divisors, whose sum is σ = 11140414122. Its totient is φ = 11140414120.

The previous prime is 11140414093. The next prime is 11140414139. The reversal of 11140414121 is 12141404111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10239213721 + 901200400 = 101189^2 + 30020^2 .

It is a cyclic number.

It is not a de Polignac number, because 11140414121 - 26 = 11140414057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11140414093 and 11140414102.

It is not a weakly prime, because it can be changed into another prime (11140414141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570207060 + 5570207061.

It is an arithmetic number, because the mean of its divisors is an integer number (5570207061).

Almost surely, 211140414121 is an apocalyptic number.

It is an amenable number.

11140414121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11140414121 is an equidigital number, since it uses as much as digits as its factorization.

11140414121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 11140414121 its reverse (12141404111), we get a palindrome (23281818232).

The spelling of 11140414121 in words is "eleven billion, one hundred forty million, four hundred fourteen thousand, one hundred twenty-one".