Base | Representation |
---|---|
bin | 11001010101001001001111… |
… | …110010110001110101101011 |
3 | 112121110010201021101210020111 |
4 | 121111021033302301311223 |
5 | 104100221300302410201 |
6 | 1032534214432235151 |
7 | 32315454640342126 |
oct | 3125111762616553 |
9 | 477403637353214 |
10 | 111404200435051 |
11 | 3255128a931507 |
12 | 105b2a6939bab7 |
13 | 4a214a91a7054 |
14 | 1d71dc63573bd |
15 | cd2d2b4dab51 |
hex | 65524fcb1d6b |
111404200435051 has 4 divisors (see below), whose sum is σ = 111488661543600. Its totient is φ = 111319739326504.
The previous prime is 111404200435039. The next prime is 111404200435069. The reversal of 111404200435051 is 150534002404111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111404200435051 - 233 = 111395610500459 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (111404200435001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42230552296 + ... + 42230554933.
It is an arithmetic number, because the mean of its divisors is an integer number (27872165385900).
Almost surely, 2111404200435051 is an apocalyptic number.
111404200435051 is a deficient number, since it is larger than the sum of its proper divisors (84461108549).
111404200435051 is an equidigital number, since it uses as much as digits as its factorization.
111404200435051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84461108548.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 111404200435051 its reverse (150534002404111), we get a palindrome (261938202839162).
The spelling of 111404200435051 in words is "one hundred eleven trillion, four hundred four billion, two hundred million, four hundred thirty-five thousand, fifty-one".
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