111410121341403 has 12 divisors (see below), whose sum is σ = 162402113679520. Its totient is φ = 73592006756976.

The previous prime is 111410121341399. The next prime is 111410121341417. The reversal of 111410121341403 is 304143121014111.

111410121341403 is a `hidden beast` number, since 1 + 1 + 1 + 4 + 1 + 0 + 1 + 213 + 41 + 403 = 666.

It is not a de Polignac number, because 111410121341403 - 2² = 111410121341399 is a prime.

It is a super-2 number, since 2×111410121341403² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111410121341903) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 56783954851 + ... + 56783956812.

Almost surely, 2^{111410121341403} is an apocalyptic number.

111410121341403 is a deficient number, since it is larger than the sum of its proper divisors (50991992338117).

111410121341403 is a wasteful number, since it uses less digits than its factorization.

111410121341403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113567911778 (or 113567911775 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 111410121341403 its reverse (304143121014111), we get a palindrome (415553242355514).

The spelling of 111410121341403 in words is "one hundred eleven trillion, four hundred ten billion, one hundred twenty-one million, three hundred forty-one thousand, four hundred three".