11141140402033 has 4 divisors (see below), whose sum is σ = 11141159157988. Its totient is φ = 11141121646080.

The previous prime is 11141140402013. The next prime is 11141140402087. The reversal of 11141140402033 is 33020404114111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7869556604529 + 3271583797504 = 2805273^2 + 1808752^2 .

It is a cyclic number.

It is not a de Polignac number, because 11141140402033 - 2¹³ = 11141140393841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11141140401989 and 11141140402007.

It is not an unprimeable number, because it can be changed into a prime (11141140402013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8456808 + ... + 9685033.

It is an arithmetic number, because the mean of its divisors is an integer number (2785289789497).

Almost surely, 2^{11141140402033} is an apocalyptic number.

It is an amenable number.

11141140402033 is a deficient number, since it is larger than the sum of its proper divisors (18755955).

11141140402033 is an equidigital number, since it uses as much as digits as its factorization.

11141140402033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18755954.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 11141140402033 its reverse (33020404114111), we get a palindrome (44161544516144).

The spelling of 11141140402033 in words is "eleven trillion, one hundred forty-one billion, one hundred forty million, four hundred two thousand, thirty-three".