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111412243433 is a prime number
BaseRepresentation
bin110011111000010101…
…1111110101111101001
3101122120111210101011102
41213300223332233221
53311133013242213
6123103155011145
711022620305151
oct1476053765751
9348514711142
10111412243433
1143282341547
1219713899ab5
13a676c743ca
14556c9a1761
152d710aa158
hex19f0afebe9

111412243433 has 2 divisors, whose sum is σ = 111412243434. Its totient is φ = 111412243432.

The previous prime is 111412243403. The next prime is 111412243469. The reversal of 111412243433 is 334342214111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75376055209 + 36036188224 = 274547^2 + 189832^2 .

It is a cyclic number.

It is not a de Polignac number, because 111412243433 - 28 = 111412243177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111412243396 and 111412243405.

It is not a weakly prime, because it can be changed into another prime (111412243403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55706121716 + 55706121717.

It is an arithmetic number, because the mean of its divisors is an integer number (55706121717).

Almost surely, 2111412243433 is an apocalyptic number.

It is an amenable number.

111412243433 is a deficient number, since it is larger than the sum of its proper divisors (1).

111412243433 is an equidigital number, since it uses as much as digits as its factorization.

111412243433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 29.

Adding to 111412243433 its reverse (334342214111), we get a palindrome (445754457544).

The spelling of 111412243433 in words is "one hundred eleven billion, four hundred twelve million, two hundred forty-three thousand, four hundred thirty-three".