Base | Representation |
---|---|
bin | 110011111000010110… |
… | …0011100010011100001 |
3 | 101122120112000112020212 |
4 | 1213300230130103201 |
5 | 3311133031131023 |
6 | 123103201343505 |
7 | 11022621321152 |
oct | 1476054342341 |
9 | 348515015225 |
10 | 111412364513 |
11 | 4328241450a |
12 | 19713937b95 |
13 | a676cb7558 |
14 | 556c9d3929 |
15 | 2d710d0e78 |
hex | 19f0b1c4e1 |
111412364513 has 2 divisors, whose sum is σ = 111412364514. Its totient is φ = 111412364512.
The previous prime is 111412364501. The next prime is 111412364587. The reversal of 111412364513 is 315463214111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107700143329 + 3712221184 = 328177^2 + 60928^2 .
It is a cyclic number.
It is not a de Polignac number, because 111412364513 - 28 = 111412364257 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111412364513.
It is not a weakly prime, because it can be changed into another prime (111412304513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55706182256 + 55706182257.
It is an arithmetic number, because the mean of its divisors is an integer number (55706182257).
Almost surely, 2111412364513 is an apocalyptic number.
It is an amenable number.
111412364513 is a deficient number, since it is larger than the sum of its proper divisors (1).
111412364513 is an equidigital number, since it uses as much as digits as its factorization.
111412364513 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8640, while the sum is 32.
Adding to 111412364513 its reverse (315463214111), we get a palindrome (426875578624).
The spelling of 111412364513 in words is "one hundred eleven billion, four hundred twelve million, three hundred sixty-four thousand, five hundred thirteen".
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