11141405535433 has 4 divisors (see below), whose sum is σ = 11146152621520. Its totient is φ = 11136658449348.

The previous prime is 11141405535413. The next prime is 11141405535439. The reversal of 11141405535433 is 33453550414111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11141405535433 - 2⁵ = 11141405535401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11141405535439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2373539523 + ... + 2373544216.

It is an arithmetic number, because the mean of its divisors is an integer number (2786538155380).

Almost surely, 2^{11141405535433} is an apocalyptic number.

It is an amenable number.

11141405535433 is a deficient number, since it is larger than the sum of its proper divisors (4747086087).

11141405535433 is an equidigital number, since it uses as much as digits as its factorization.

11141405535433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4747086086.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 11141405535433 its reverse (33453550414111), we get a palindrome (44594955949544).

The spelling of 11141405535433 in words is "eleven trillion, one hundred forty-one billion, four hundred five million, five hundred thirty-five thousand, four hundred thirty-three".