Base | Representation |
---|---|
bin | 10000001101100111111… |
… | …111100011101001101011 |
3 | 10221111210102022101122221 |
4 | 100031213333203221223 |
5 | 121223230124302021 |
6 | 2211455053254511 |
7 | 143331313214125 |
oct | 20154777435153 |
9 | 3844712271587 |
10 | 1114141244011 |
11 | 39a560760a14 |
12 | 15bb17794437 |
13 | 810a873b793 |
14 | 3bcd362a215 |
15 | 1deac1d4241 |
hex | 10367fe3a6b |
1114141244011 has 4 divisors (see below), whose sum is σ = 1114143355800. Its totient is φ = 1114139132224.
The previous prime is 1114141243951. The next prime is 1114141244039. The reversal of 1114141244011 is 1104421414111.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 1114141244011 - 27 = 1114141243883 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1114141244611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 486300 + ... + 1569958.
It is an arithmetic number, because the mean of its divisors is an integer number (278535838950).
Almost surely, 21114141244011 is an apocalyptic number.
1114141244011 is a deficient number, since it is larger than the sum of its proper divisors (2111789).
1114141244011 is a wasteful number, since it uses less digits than its factorization.
1114141244011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2111788.
The product of its (nonzero) digits is 512, while the sum is 25.
Adding to 1114141244011 its reverse (1104421414111), we get a palindrome (2218562658122).
The spelling of 1114141244011 in words is "one trillion, one hundred fourteen billion, one hundred forty-one million, two hundred forty-four thousand, eleven".
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