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111414155513 is a prime number
BaseRepresentation
bin110011111000011001…
…1010001100011111001
3101122120122101112001012
41213300303101203321
53311134010434023
6123103304003305
711022642460553
oct1476063214371
9348518345035
10111414155513
1143283428081
1219714460535
13a67749380b
14556cd3c4d3
152d71336978
hex19f0cd18f9

111414155513 has 2 divisors, whose sum is σ = 111414155514. Its totient is φ = 111414155512.

The previous prime is 111414155497. The next prime is 111414155543. The reversal of 111414155513 is 315551414111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77282332009 + 34131823504 = 277997^2 + 184748^2 .

It is a cyclic number.

It is not a de Polignac number, because 111414155513 - 24 = 111414155497 is a prime.

It is a super-2 number, since 2×1114141555132 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 111414155513.

It is not a weakly prime, because it can be changed into another prime (111414155543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55707077756 + 55707077757.

It is an arithmetic number, because the mean of its divisors is an integer number (55707077757).

Almost surely, 2111414155513 is an apocalyptic number.

It is an amenable number.

111414155513 is a deficient number, since it is larger than the sum of its proper divisors (1).

111414155513 is an equidigital number, since it uses as much as digits as its factorization.

111414155513 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6000, while the sum is 32.

Adding to 111414155513 its reverse (315551414111), we get a palindrome (426965569624).

The spelling of 111414155513 in words is "one hundred eleven billion, four hundred fourteen million, one hundred fifty-five thousand, five hundred thirteen".