Search a number
-
+
1114224224131 is a prime number
BaseRepresentation
bin10000001101101100111…
…100000110011110000011
310221112000012110012222201
4100031230330012132003
5121223412400133011
62211511220014031
7143333341431514
oct20155474063603
93845005405881
101114224224131
1139a5a3588127
1215bb3b531317
13810bc9a3445
143bd0066aa0b
151deb4625cc1
hex1036cf06783

1114224224131 has 2 divisors, whose sum is σ = 1114224224132. Its totient is φ = 1114224224130.

The previous prime is 1114224224083. The next prime is 1114224224147. The reversal of 1114224224131 is 1314224224111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1114224224131 - 215 = 1114224191363 is a prime.

It is a super-2 number, since 2×11142242241312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1114224224131.

It is not a weakly prime, because it can be changed into another prime (1114224224831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557112112065 + 557112112066.

It is an arithmetic number, because the mean of its divisors is an integer number (557112112066).

Almost surely, 21114224224131 is an apocalyptic number.

1114224224131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114224224131 is an equidigital number, since it uses as much as digits as its factorization.

1114224224131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3072, while the sum is 28.

Adding to 1114224224131 its reverse (1314224224111), we get a palindrome (2428448448242).

The spelling of 1114224224131 in words is "one trillion, one hundred fourteen billion, two hundred twenty-four million, two hundred twenty-four thousand, one hundred thirty-one".