Base | Representation |
---|---|
bin | 110011111000101011… |
… | …0100111011010110011 |
3 | 101122121021211012122102 |
4 | 1213301112213122303 |
5 | 3311143343420313 |
6 | 123104234331015 |
7 | 11023114305143 |
oct | 1476126473263 |
9 | 348537735572 |
10 | 111423420083 |
11 | 43288685748 |
12 | 19717589a6b |
13 | a679388701 |
14 | 5570270923 |
15 | 2d72066a58 |
hex | 19f15a76b3 |
111423420083 has 2 divisors, whose sum is σ = 111423420084. Its totient is φ = 111423420082.
The previous prime is 111423420077. The next prime is 111423420103. The reversal of 111423420083 is 380024324111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111423420083 - 210 = 111423419059 is a prime.
It is not a weakly prime, because it can be changed into another prime (111423425083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55711710041 + 55711710042.
It is an arithmetic number, because the mean of its divisors is an integer number (55711710042).
Almost surely, 2111423420083 is an apocalyptic number.
111423420083 is a deficient number, since it is larger than the sum of its proper divisors (1).
111423420083 is an equidigital number, since it uses as much as digits as its factorization.
111423420083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 111423420083 its reverse (380024324111), we get a palindrome (491447744194).
The spelling of 111423420083 in words is "one hundred eleven billion, four hundred twenty-three million, four hundred twenty thousand, eighty-three".
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