11142435433 has 2 divisors, whose sum is σ = 11142435434. Its totient is φ = 11142435432.

The previous prime is 11142435389. The next prime is 11142435439. The reversal of 11142435433 is 33453424111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10389317184 + 753118249 = 101928^2 + 27443^2 .

It is an emirp because it is prime and its reverse (33453424111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11142435433 - 2²⁵ = 11108881001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11142435395 and 11142435404.

It is not a weakly prime, because it can be changed into another prime (11142435439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571217716 + 5571217717.

It is an arithmetic number, because the mean of its divisors is an integer number (5571217717).

Almost surely, 2^11142435433 is an apocalyptic number.

It is an amenable number.

11142435433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11142435433 is an equidigital number, since it uses as much as digits as its factorization.

11142435433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17280, while the sum is 31.

Adding to 11142435433 its reverse (33453424111), we get a palindrome (44595859544).

The spelling of 11142435433 in words is "eleven billion, one hundred forty-two million, four hundred thirty-five thousand, four hundred thirty-three".