Base | Representation |
---|---|
bin | 10100110000010010… |
… | …00011000001111011 |
3 | 1001202112110202110221 |
4 | 22120021003001323 |
5 | 140304431140011 |
6 | 5041353120511 |
7 | 543056126641 |
oct | 123011030173 |
9 | 31675422427 |
10 | 11142443131 |
11 | 47a8689496 |
12 | 21ab6b9137 |
13 | 10875aba21 |
14 | 779b8d191 |
15 | 453329971 |
hex | 29824307b |
11142443131 has 8 divisors (see below), whose sum is σ = 11159692704. Its totient is φ = 11125208640.
The previous prime is 11142443071. The next prime is 11142443177. The reversal of 11142443131 is 13134424111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11142443131 - 27 = 11142443003 is a prime.
It is a super-2 number, since 2×111424431312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11142443096 and 11142443105.
It is not an unprimeable number, because it can be changed into a prime (11142440131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3033426 + ... + 3037096.
It is an arithmetic number, because the mean of its divisors is an integer number (1394961588).
Almost surely, 211142443131 is an apocalyptic number.
11142443131 is a deficient number, since it is larger than the sum of its proper divisors (17249573).
11142443131 is a wasteful number, since it uses less digits than its factorization.
11142443131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7541.
The product of its digits is 1152, while the sum is 25.
Adding to 11142443131 its reverse (13134424111), we get a palindrome (24276867242).
The spelling of 11142443131 in words is "eleven billion, one hundred forty-two million, four hundred forty-three thousand, one hundred thirty-one".
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