111426433 has 2 divisors, whose sum is σ = 111426434. Its totient is φ = 111426432.

The previous prime is 111426391. The next prime is 111426437. The reversal of 111426433 is 334624111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60403984 + 51022449 = 7772^2 + 7143^2 .

It is an emirp because it is prime and its reverse (334624111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111426433 - 2⁹ = 111425921 is a prime.

It is a super-2 number, since 2×111426433² = 24831699942206978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 111426398 and 111426407.

It is not a weakly prime, because it can be changed into another prime (111426437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55713216 + 55713217.

It is an arithmetic number, because the mean of its divisors is an integer number (55713217).

Almost surely, 2^111426433 is an apocalyptic number.

It is an amenable number.

111426433 is a deficient number, since it is larger than the sum of its proper divisors (1).

111426433 is an equidigital number, since it uses as much as digits as its factorization.

111426433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1728, while the sum is 25.

The square root of 111426433 is about 10555.8719677723. The cubic root of 111426433 is about 481.2042001054.

The spelling of 111426433 in words is "one hundred eleven million, four hundred twenty-six thousand, four hundred thirty-three".