1114312144331 has 4 divisors (see below), whose sum is σ = 1117468836312. Its totient is φ = 1111155452352.

The previous prime is 1114312144313. The next prime is 1114312144399. The reversal of 1114312144331 is 1334412134111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1114312144331 is a prime.

It is a super-2 number, since 2×1114312144331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1114312144294 and 1114312144303.

It is not an unprimeable number, because it can be changed into a prime (1114312141331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1578345461 + ... + 1578346166.

It is an arithmetic number, because the mean of its divisors is an integer number (279367209078).

Almost surely, 2^{1114312144331} is an apocalyptic number.

1114312144331 is a deficient number, since it is larger than the sum of its proper divisors (3156691981).

1114312144331 is an equidigital number, since it uses as much as digits as its factorization.

1114312144331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3156691980.

The product of its digits is 3456, while the sum is 29.

Adding to 1114312144331 its reverse (1334412134111), we get a palindrome (2448724278442).

The spelling of 1114312144331 in words is "one trillion, one hundred fourteen billion, three hundred twelve million, one hundred forty-four thousand, three hundred thirty-one".