Base | Representation |
---|---|
bin | 10100110000011001… |
… | …11011111000100001 |
3 | 1001202121101112200212 |
4 | 22120030323320201 |
5 | 140310211244213 |
6 | 5041431023505 |
7 | 543100603445 |
oct | 123014737041 |
9 | 31677345625 |
10 | 11143462433 |
11 | 47a9215294 |
12 | 21abb0ab95 |
13 | 108787796c |
14 | 779d76825 |
15 | 45347b9a8 |
hex | 29833be21 |
11143462433 has 2 divisors, whose sum is σ = 11143462434. Its totient is φ = 11143462432.
The previous prime is 11143462409. The next prime is 11143462597. The reversal of 11143462433 is 33426434111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8139107089 + 3004355344 = 90217^2 + 54812^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11143462433 is a prime.
It is a super-4 number, since 4×111434624334 (a number of 41 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11143462433.
It is not a weakly prime, because it can be changed into another prime (11143462333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571731216 + 5571731217.
It is an arithmetic number, because the mean of its divisors is an integer number (5571731217).
Almost surely, 211143462433 is an apocalyptic number.
It is an amenable number.
11143462433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11143462433 is an equidigital number, since it uses as much as digits as its factorization.
11143462433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 32.
Adding to 11143462433 its reverse (33426434111), we get a palindrome (44569896544).
The spelling of 11143462433 in words is "eleven billion, one hundred forty-three million, four hundred sixty-two thousand, four hundred thirty-three".
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