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111443413051 is a prime number
BaseRepresentation
bin110011111001010001…
…0111000100000111011
3101122122200102221211201
41213302202320200323
53311214003204201
6123110231035031
711023446244525
oct1476242704073
9348580387751
10111443413051
11432989a0763
121972220ba77
13a680568879
145572b96a15
152d73bb5801
hex19f28b883b

111443413051 has 2 divisors, whose sum is σ = 111443413052. Its totient is φ = 111443413050.

The previous prime is 111443413031. The next prime is 111443413061. The reversal of 111443413051 is 150314344111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111443413051 - 215 = 111443380283 is a prime.

It is not a weakly prime, because it can be changed into another prime (111443413001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55721706525 + 55721706526.

It is an arithmetic number, because the mean of its divisors is an integer number (55721706526).

Almost surely, 2111443413051 is an apocalyptic number.

111443413051 is a deficient number, since it is larger than the sum of its proper divisors (1).

111443413051 is an equidigital number, since it uses as much as digits as its factorization.

111443413051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 111443413051 its reverse (150314344111), we get a palindrome (261757757162).

The spelling of 111443413051 in words is "one hundred eleven billion, four hundred forty-three million, four hundred thirteen thousand, fifty-one".