Search a number
-
+
11144430001 = 69911594111
BaseRepresentation
bin10100110000100001…
…01000000110110001
31001202200012200221201
422120100220012301
5140310433230001
65041503451201
7543112043365
oct123020500661
931680180851
1011144430001
1147a9816231
1221b02b6b01
131087b261a3
1477a1492a5
154535bd501
hex2984281b1

11144430001 has 4 divisors (see below), whose sum is σ = 11146031104. Its totient is φ = 11142828900.

The previous prime is 11144429999. The next prime is 11144430023. The reversal of 11144430001 is 10003444111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10003444111 = 48720540953.

It is a cyclic number.

It is not a de Polignac number, because 11144430001 - 21 = 11144429999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11144430071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 790065 + ... + 804046.

It is an arithmetic number, because the mean of its divisors is an integer number (2786507776).

Almost surely, 211144430001 is an apocalyptic number.

It is an amenable number.

11144430001 is a deficient number, since it is larger than the sum of its proper divisors (1601103).

11144430001 is an equidigital number, since it uses as much as digits as its factorization.

11144430001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1601102.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11144430001 its reverse (10003444111), we get a palindrome (21147874112).

The spelling of 11144430001 in words is "eleven billion, one hundred forty-four million, four hundred thirty thousand, one".

Divisors: 1 6991 1594111 11144430001