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111444414281 is a prime number
BaseRepresentation
bin110011111001010011…
…0101100111101001001
3101122122202022211021022
41213302212230331021
53311214232224111
6123110304322225
711023460614544
oct1476246547511
9348582284238
10111444414281
1143299514a22
1219722613375
13a680829505
145572d7785b
152d73d122db
hex19f29acf49

111444414281 has 2 divisors, whose sum is σ = 111444414282. Its totient is φ = 111444414280.

The previous prime is 111444414251. The next prime is 111444414313. The reversal of 111444414281 is 182414444111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68919375625 + 42525038656 = 262525^2 + 206216^2 .

It is a cyclic number.

It is not a de Polignac number, because 111444414281 - 26 = 111444414217 is a prime.

It is a super-2 number, since 2×1114444142812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111444414251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55722207140 + 55722207141.

It is an arithmetic number, because the mean of its divisors is an integer number (55722207141).

Almost surely, 2111444414281 is an apocalyptic number.

It is an amenable number.

111444414281 is a deficient number, since it is larger than the sum of its proper divisors (1).

111444414281 is an equidigital number, since it uses as much as digits as its factorization.

111444414281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 16384, while the sum is 35.

Adding to 111444414281 its reverse (182414444111), we get a palindrome (293858858392).

The spelling of 111444414281 in words is "one hundred eleven billion, four hundred forty-four million, four hundred fourteen thousand, two hundred eighty-one".